PHP question

[Mapantz]

I am not really great at this stuff and only know a few basics, so this has me stumped..

Is there any reason why the below code doesn't work, but entering the numbers manually does?

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$previousDay   	=    '<?php echo date("Y"); ?>'.'-';
$previousDay   	.=   '<?php echo date("m"); ?>';
$previousDay   	.=   '-'.'<?php echo date("d"); ?>';

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$previousDay   	=    '2019'.'-';
$previousDay   	.=   '11';
$previousDay   	.=   '-'.'26';

Many thanks!

[saratogaWX]

That is a bit of odd code..
Some things to keep in mind:
1) string literals inside single-quoted strings aren't evaluated by PHP. Only string literals within double quoted strings are evaluated.
2) there's a much simpler way to ensure your $previousDay variable inside PHP is set with the date of yesterday:

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$previousDay = date("Y-m-d",strtotime("yesterday"));

[Mapantz]

Wow yeah, that does simplify what I was trying to achieve.

Many thanks, Ken. Much appreciated!